Gracefully print out debug messages even outside app context

The flask.current_app object depends on the application context
existing. In the case that no such context existing, then we still log
out information, gracefully with this commit.

1 files changed, 9 insertions, 3 deletions

diff --git a/gn3/debug.py b/gn3/debug.py
index acc2402..3c88bd3 100644
--- a/gn3/debug.py
+++ b/gn3/debug.py
@@ -2,11 +2,17 @@
 import logging
 from flask import current_app
 
-logger = logging.getLogger(__name__)
+__this_module_name__ == __name__
+
+def getLogger():
+    return (
+        logging.getLogger(__name__)
+        if not bool(current_app)
+        else current_app.logger)
 
 def __pk__(*args):
     value = args[-1]
     title_vals = " => ".join(args[0:-1])
-    current_app.logger.setLevel(logging.DEBUG) # Force debug level since we assume we are using it!
-    current_app.logger.debug("%s: %s", title_vals, value)
+    logger = getLogger()
+    logger.debug("%s: %s", title_vals, value)
     return value