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Cell arrays are a little tricky in Matlab.
Consider this example.
C=num2cell(rand(2,3))
C =
[0.4565] [0.8214] [0.6154]
[0.0185] [0.4447] [0.7919]
C{1,2} % this is the contents of this cell (could be a vector or a string)
ans =
0.8214
C{1:2,2} % this is the contents of these cells - returns multiple
answers!
ans =
0.8214
ans =
0.4447
A = C(1:2,2) % this is a slice of the cell array
ans =
[0.8214]
[0.4447]
A{1} % A is itself a cell array
ans =
0.8214
>> C(1:2,2)=0 % can't assign a scalar to a cell array
C(1:2,2)=0
??? Conversion to cell from double is not possible.
>> C(1:2,2)={0;0} % can assign a cell array to a cell array
C(1:2,2)={0;0}
C =
[0.4565] [0] [0.6154]
[0.0185] [0] [0.7919]
BTW, I use cell arrays for evidence for 2 reasons:
1. [] indicates missing values
2. it can easily represent vector-valued nodes
The following example makes this clear
C{1,1} = []
C{2,1} = rand(3,1)
C =
[] [0] [0.6154]
[3x1 double] [0] [0.7919]
Hope this helps,
Kevin
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